## Let's count to infinity!

### Re: Let's count to infinity!

${8}\choose{3}$

(Not sure what number we are really on, but I'll say 56.)
Math - It's in you to give.

SpikedMath

Posts: 133
Joined: Mon Feb 07, 2011 1:31 am

### Re: Let's count to infinity!

$3.(2.3^2+1)$
Spoiler! :
The Spanish Inquisition

Clearly every even integer greater than 2 can be expressed as the sum of two primes.
I have discovered a truly wonderful proof of this proposition, but the signature is too small to contain it.

Ardilla
High School

Posts: 26
Joined: Fri Feb 11, 2011 6:15 pm
Location: Argentina

### Re: Let's count to infinity!

Pretty sure that's what we were supposed to be up to.

$2\cdot4!\,+\,3!\,+\,2\cdot2!\$

DeathRowKitty
Mathlete

Posts: 68
Joined: Fri Feb 11, 2011 8:38 am

### Re: Let's count to infinity!

$\text{The }$$\frac{4^4}{4*4}+1$$\!\text{th prime}$
Last edited by WhoDatMath on Mon Feb 28, 2011 9:31 am, edited 1 time in total.
WhoDatMath
Mathlete

Posts: 78
Joined: Thu Feb 10, 2011 4:53 pm

### Re: Let's count to infinity!

(That should be the 17th prime, not the 16th)

$\frac{5!}{2}$

DeathRowKitty
Mathlete

Posts: 68
Joined: Fri Feb 11, 2011 8:38 am

### Re: Let's count to infinity!

Duh, that's what I said

$\text{The }$$\frac{4^4}{4*4}+\sqrt{4}$$\!\text{th prime}$
WhoDatMath
Mathlete

Posts: 78
Joined: Thu Feb 10, 2011 4:53 pm

### Re: Let's count to infinity!

I hope I'm right
$4+\frac{4!}{.4}+\sqrt{4}$
theanalyst
Kindergarten

Posts: 1
Joined: Sun Feb 27, 2011 1:11 pm

### Re: Let's count to infinity!

[(4^4)/4 - .4]
(That outer set of square brackets is the greatest integer function)

So, nobody wants to get to 64?

63 is pretty far from infinity...
bmonk
University

Posts: 133
Joined: Thu Feb 10, 2011 4:03 pm

### Re: Let's count to infinity!

Alas, nobody is interested in the (5! / √4) + 3 + 2 - 1-th number???
bmonk
University

Posts: 133
Joined: Thu Feb 10, 2011 4:03 pm

### Re: Let's count to infinity!

the only number N that can be represented as N=(a^b)^(b^a)=(b^a)^(a^b)
There was an open question which i have asked many proffesors and fellow mathematicians, but none were able to answer:

Is there a function f:R->R (not necessarily continuous on ALL of R) which:
for every linear function g(x)=m*x+n, there is a number X for which g is the tangent of f in? (for each x g(x)=f(X)+f'(X)(x-X))
i think not.

(i almost solved it - using a small set theory tweak and a big topology tweak)
Ekuurh
Elementary School

Posts: 14
Joined: Tue Apr 19, 2011 12:28 pm

### Re: Let's count to infinity!

In hexadecimal, this number is 42.
Math - It's in you to give.

SpikedMath

Posts: 133
Joined: Mon Feb 07, 2011 1:31 am

### Re: Let's count to infinity!

The US route from Chicago to LA, plus one.
bmonk
University

Posts: 133
Joined: Thu Feb 10, 2011 4:03 pm

### Re: Let's count to infinity!

let f(n) be the n-th Fibonacci number (with f(0)=1, f(1)=1, f(n+2) = f(n+1)+f(n)):
The only number that can be represented as f(n)*f(f(n)^f(n+1))=f(1+f(n)^f(n+1))+f(f(n)*f(n+1))
I'll make it easier for you:
n=2.
There was an open question which i have asked many proffesors and fellow mathematicians, but none were able to answer:

Is there a function f:R->R (not necessarily continuous on ALL of R) which:
for every linear function g(x)=m*x+n, there is a number X for which g is the tangent of f in? (for each x g(x)=f(X)+f'(X)(x-X))
i think not.

(i almost solved it - using a small set theory tweak and a big topology tweak)
Ekuurh
Elementary School

Posts: 14
Joined: Tue Apr 19, 2011 12:28 pm

### Re: Let's count to infinity!

13^2 - 10^2
bmonk
University

Posts: 133
Joined: Thu Feb 10, 2011 4:03 pm

### Re: Let's count to infinity!

[img]http://spikedmath.com/cgi-bin/mimetex.cgi?{8}%5Cchoose{4}[/img]
There was an open question which i have asked many proffesors and fellow mathematicians, but none were able to answer:

Is there a function f:R->R (not necessarily continuous on ALL of R) which:
for every linear function g(x)=m*x+n, there is a number X for which g is the tangent of f in? (for each x g(x)=f(X)+f'(X)(x-X))
i think not.

(i almost solved it - using a small set theory tweak and a big topology tweak)
Ekuurh
Elementary School

Posts: 14
Joined: Tue Apr 19, 2011 12:28 pm

### Re: Let's count to infinity!

Ekuurh wrote:[img]http://spikedmath.com/cgi-bin/mimetex.cgi?{8}%5Cchoose{4}[/img]

damn, it ain't working, just go to
http://spikedmath.com/cgi-bin/mimetex.cgi?{8}%5Cchoose{4}
There was an open question which i have asked many proffesors and fellow mathematicians, but none were able to answer:

Is there a function f:R->R (not necessarily continuous on ALL of R) which:
for every linear function g(x)=m*x+n, there is a number X for which g is the tangent of f in? (for each x g(x)=f(X)+f'(X)(x-X))
i think not.

(i almost solved it - using a small set theory tweak and a big topology tweak)
Ekuurh
Elementary School

Posts: 14
Joined: Tue Apr 19, 2011 12:28 pm

### Re: Let's count to infinity!

I'm slipping!

How about: [(100* √2)+1] / 2

You were right--forgot the divide by 2. Alas--I'm one of those mathematicians who can't calculate, and even find counting a chore.
Last edited by bmonk on Wed Jun 01, 2011 10:19 am, edited 1 time in total.
bmonk
University

Posts: 133
Joined: Thu Feb 10, 2011 4:03 pm

### Re: Let's count to infinity!

I think you need a division by 2 bmonk.

I'll do an easy one: $\frac{12^2}{2}$
Math - It's in you to give.

SpikedMath

Posts: 133
Joined: Mon Feb 07, 2011 1:31 am

### Re: Let's count to infinity!

The (7x3)st prime.
bmonk
University

Posts: 133
Joined: Thu Feb 10, 2011 4:03 pm

### Re: Let's count to infinity!

74
Spoiler! :
The Spanish Inquisition

Clearly every even integer greater than 2 can be expressed as the sum of two primes.
I have discovered a truly wonderful proof of this proposition, but the signature is too small to contain it.

Ardilla
High School

Posts: 26
Joined: Fri Feb 11, 2011 6:15 pm
Location: Argentina

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