203
Geeky Revenge - March 24, 2010Rating: 4.9/5 (16 votes cast)
Facebook Page // Twitter Page
11 Comments
Leave a comment
Profile pictures are tied to your email address and can
be set up at Gravatar.
Click here for recent comments.
(Note: You must have javascript enabled to leave comments, otherwise you will get a comment submission error.)
(Note: You must have javascript enabled to leave comments, otherwise you will get a comment submission error.)
"Things to Try on Math Tests" Chapter 1.
i once got my teacher to make a smiley substitution in class... also had a teacher who raised things to the flower power. was freakin awesome
This one goes up on the bulletin board with the classic Foxtrot physics test comic.
My calc II prof did that on several occasions when the majority of the class wasn't getting what was going on.. I remember it clearly, "the integral of the squiggle dx is squigglex +C!"
Shouldn't that have been (squiggle^n)/n-1?
integirl is correct if the squiggle was a constant and the integral was indefinite. The power rule is a more general form if the squiggle was a constant multiplied by a power of x, it would not hold if there was a trigonometric function involved. Also you are missing the most crucial part, + C.
oh i was wondering why he wanted revenge
I see--this one is the continuation of yesterday's looking for revenge. He he he! Talk about a perfectionist.
A math teacher I once knew said he was going through security 50 or so years back with a bunch of new pencils. The guard noticed them, pointed at the erasers, and said, "This is because nobody is perfect, huh?" and laughed when the teacher ruefully agreed.
I remember I needed to use a symbol on a mechanics problem set...so I ended up using d(triforce)/dt in a differential equation.
Lol. This reminds me of the time I wrote an entire calculus exam using roman numerals... from then on, the "read this before you start" paragraphs always included "write your numerical answers using arabic numerals" =P
Math n00b, he used the quadratic formula! Use the pq formula. (-p/2)+/- sqrt((p/2)^2 - q). So simple.